When replacing the audio output transformer on a radio, the replacement should match the impedance of the original as close as possible. If the wrong transformer is used, the results can be low output and loss of tone quality. Universal output transformers are available which have multi-tapped primary and secondary windings to match a wide impedance range.

It is not uncommon for the vintage radio collector to have various output transformers laying about that have been pulled from parts sets, or have been obtained at swap meets. Often times, the primary and secondary impedance information is not available for these units, and it would be nice to have that information to be able to use these in a set that needs a new output transformer.

The average beam power output tube, such as the 6V6 requires a load of around 5,000 ohms, and the average speaker voice coil can vary from as low as 1 ohm to 8 ohms or more. So, how do we determine which of our output transformers will match that impedance range? With some simple test equipment and ohms law, we can calculate the impedance of an output transformer, but first lets look at the function of an output transformer and how it works.

To keep the math simple, lets assume an output tube is supplying a 100 volt ac signal to the primary of an output transformer with a 10:1 winding ratio, and the secondary is feeding a 10 ohm voice coil (see figure 1A below). With 100 volts across the primary, there will be 10 volts across the voice coil connected to the secondary. Using ohms law, there will be 1 amp of current flowing in the voice coil.

I = E/R I = 10/10 = 1 ampereFor further simplification we will assume 100% efficiency in the transformer. Since we have a 10:1 ratio, the current flowing in the primary will be

Z = E/I Z = 100/.1 = 1,000 ohmsNow if we decrease the impedance of the load, what happens to the impedance in the primary? If we place another 10 ohm voice coil in parallel with the original one, we now have a 5 ohm load (see figure 1B below). Using ohms law again we see that the current in the secondary is now 2 amperes.

I = E/R I = 10/5 = 2 amperesThis means that the current in the primary also doubles to

Z = E/I Z = 100/.2 = 500 ohmsThis is called the

To determine the turns ratio we apply an ac voltage to the primary, and measure the voltage in the secondary. The voltage on the secondary will be stepped down by a proportional amount determined by the turns ratio of the transformer. Figure 2 below shows the schematic diagram of the test set-up. A variable auto-transformer (sometimes referred to by the brand name Variac) is used to apply the variable ac to the primary (see note below). An ac voltmeter is connected to the secondary to measure the output voltage. To make the calculation of the turns ratio easy, the input voltage is increased until the voltage on the secondary reads 1 volt. With the secondary reading 1 volt, measure the input voltage to the primary. Since the voltage on the secondary is set to 1 volt, the voltage measured on the primary will be the turns ratio. For example, if the voltage on the primary measures 25 volts, the turns ratio is 25:1 as illustrated in figure 2 below.

**Note:** An auto-transformer does not provide isolation from the ac line.
For safety reasons, the auto-transformer should be used in conjunction with
a 1:1 isolation transformer.

Now, armed with the turns ratio, we can calculate the impedance ratio and the impedance that will be reflected to the primary with a given load in the secondary. Remember we said earlier that the impedance ratio is the square of the turns ratio. With our 25:1 turns ratio transformer in figure 2, the impedance ratio is the turns ratio squared or, 25 X 25 = 625:1. So if the transformer is working into an 8 ohm load, the impedance that will be reflected to the primary will be the impedance ratio (625) multiplied by the load impedance (8 ohms), equal 5,000 ohms. If the load in the secondary is changed to a 4 ohm load, the reflected impedance in the primary would be 625 X 4 = 2,500 ohms.

So it can be seen that the turns ratio of the transformer determines what impedance will be reflected to the primary by the load impedance of the secondary, and that an improper load on the secondary can have several effects:

- if the load impedance is too low this will increase the current in the transformer windings. This also reduces the primary impedance that the output tube sees which increases tube current flow.
- if the load impedance is too high, this reflects a higher than normal impedance in the primary for the output tube.
- poor sound quality and lack of volume.

With this information we can determine what the turns ratio should be. By dividing the secondary load of 8 ohms into the 7,000 ohms required by the 6F6, we get an impedance ratio of 875:1. If the impedance ratio is the square of the turns ratio, then the turns ratio is the square root of the impedance ratio. Taking the square root of 875 gives us a 29.6:1 ratio, so an output transformer with a turns ratio in this range should work.

By using the test procedure outlined above we can test our spare output transformers to see if we have one that will meet our approximate 30:1 turns ratio requirement.

Primary Load Impedance | 18,000 | 14,000 | 10,000 | 8,000 | 7,000 | 5,000 | 4,000 | 2,000 |
---|---|---|---|---|---|---|---|---|

Single Ended Class A | 1F4 1F5 | 1J5 1LB4 1T5 10 12A 12A7 38 | 6G6 19 41 49 | 1C5 1G5 1Q5 1S4 3Q5 3S4 6K6 6A4 7A5 7B5 12A6 14A5 | 2A5 6F6 12A 42 47 | 3B5 6AQ5 6L6 6V6 7C5 12A5 14C5 50 71A | 6AC5 12A4 43 45 117L7 | 2A3 6Y6 7A5 25L6 35A5 35B5 35L6 48 50A5 50B5 50L6 |

Push Pull Plate to Plate | 6K6 47 | 6AQ5 6F6 6L6 6V6 42 | 6V6 12A5 50 71A | 2A3 45 |

**Note:** The load resistance will vary somewhat depending upon the voltages
applied to the tube and the type of bias (fixed or self-bias). Consult a tube
manual for actual load resistance under different voltages and bias.